The following Java program finds the number of digits in a number. This program converts the number to a string and then prints its length,

public class DigitsInNumber {

    public static void main(String[] args ) {
        int number = 94487;
        String s = String.valueOf(number);
        System.out.println(number + " has "+ s.length()+" digits");
    }
}

The following is an alternate Java implementation which finds number of digits in a number without converting it into a string. This program divides the number by 10 until the number becomes 0. The number of iterations is equal to the number of digits.

public class DigitsInNumber {

    public static void main(String[] args ) {
        int original_number = 1119;
        int n = original_number;
        int digits = 0;
        while(n > 0 ) {
            digits ++;
            n = n / 10;
        }
        System.out.println(original_number + " has "+ digits+" digits");
    }
}